Answer
a) .065 meters
b) .51 seconds
Work Step by Step
a) We find:
$A = \frac{mg}{k} = \frac{(.49)(9.81)}{74}=\fbox{.065 meters}$
b) We use the equation for period to find:
$T = 2 \pi \sqrt{\frac{m}{k}} = 2 \pi \sqrt{\frac{.49}{74}} =\fbox{.51 seconds}$
