Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 13 - Exercises and Problems: 58

Answer

$T=2\pi \sqrt{\frac{2R}{g}}$

Work Step by Step

We know that $\omega=\sqrt{\frac{MgL}{I}}$ We also know that $T=\frac{2\pi}{\omega}$ $\implies T=2\pi \sqrt{\frac{I}{MgL}}$ $Implies $ $ T=2\pi \sqrt{\frac{2MR^2}{MgR}}$ This simplifies to: $T=2\pi \sqrt{\frac{2R}{g}}$
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