## Essential University Physics: Volume 1 (3rd Edition)

$T=2\pi \sqrt{\frac{2R}{g}}$
We know that $\omega=\sqrt{\frac{MgL}{I}}$ We also know that $T=\frac{2\pi}{\omega}$ $\implies T=2\pi \sqrt{\frac{I}{MgL}}$ $Implies$ $T=2\pi \sqrt{\frac{2MR^2}{MgR}}$ This simplifies to: $T=2\pi \sqrt{\frac{2R}{g}}$