Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 12 - Exercises and Problems - Page 214: 18


The boy should sit .6 meters left of the pivot point.

Work Step by Step

We know that for the scale to read zero, the net torque must be 0. We know that the center of mass of the board is in the center, which is .4 meters right of the axis of rotation. Thus, we find how far away the boy should be on the left side: $40r=(60)(.4)$ $r=.6 \ m$
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