#### Answer

The torques still sum to zero.

#### Work Step by Step

Recall that the net torque is equal to the sum of all of the torques, which are each given by $\vec{r}\times\vec{F}$. In addition, recall that the position vector is given by the vector $\vec{r}=x\hat{i}+y\hat{j}$, where x,y are the x and y distances the applied torque is from the axis of rotation, respectively. Doing this, we find that all of the torques still sum to zero.