#### Answer

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#### Work Step by Step

We know that the torque about the rigid end of the log is given as
$mgx_{cm}-Td=0$
We plug in the known values to obtain:
$(7.5)x_m-(6.2)(23-4)=0$
This simplifies to:
$x_{cm}=16m$

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Published by
Pearson

ISBN 10:
0321993721

ISBN 13:
978-0-32199-372-4

Please see the work below.

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