Answer
Please see the work below.
Work Step by Step
We know that the torque about the rigid end of the log is given as
$mgx_{cm}-Td=0$
We plug in the known values to obtain:
$(7.5)x_m-(6.2)(23-4)=0$
This simplifies to:
$x_{cm}=16m$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 12 - Exercises and Problems - Page 214: 17
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