Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 11 - Exercises and Problems - Page 201: 48



Work Step by Step

First, using the fact that torque equals $\vec{r}\times\vec{F}$, we find that the y-component of the torque is 2.3 Newtons. Thus, the force's magnitude is: $|F|=\sqrt{2.3^2+3.1^2}=3.86$ We simplify the equation for torque: $\tau=rFsin\theta \\ \frac{\tau}{rF}=sin\theta \\ \theta = sin^{-1}(\frac{\tau}{rF})=sin^{-1}(\frac{4.6}{3.86\times2})=36.57^{\circ}$
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