Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 11 - Exercises and Problems: 29

Answer

Please see the work below.

Work Step by Step

According to law of conservation of energy $L_i\omega_i=L_f \omega_f$ $\implies (\frac{2}{5}mr_i)^2(\frac{2\pi}{T})=(\frac{2}{5}mr_f^2)(\frac{2\pi}{T_f})$ This simplifies to: $\frac{r_i^2}{T_f}=\frac{r_f^2}{T_f}$ $\implies T_f=\frac{r_f^2}{r_i^2}T_i=\frac{(7\times 10^8)^2}{(1\times 10^{13})^2}(1.4\times 10^6)=0.00686yr$
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