Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 11 - Exercises and Problems: 38

Answer

Please see the work below.

Work Step by Step

It is given that $\vec{A}^{\,}.\vec{B}^{\,}=\frac{1}{2}|\vec{A}^{\,}\times \vec{B}^{\,}|$ We know that $\vec{A}^{\,}.\vec{B}^{\,}=ABcos\theta$ $\vec{A}^{\,}\times \vec{B}^{\,}=ABsin\theta$ $\implies ABcos\theta=\frac{1}{2} ABsin\theta$ $2=tan\theta$ $\theta=tan^{-1}(2)=63.4^{\circ}$
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