Answer
a. Find the amount of heat needed for steel.
$$Q = cm \Delta T$$
$$=\frac{450 J}{kg \cdot ^{\circ}C}(10 kg)(100^{\circ}C - 0^{\circ}C ) = 450,000 J$$
b. Now perform the calculation for water.
$$Q = cm \Delta T$$
$$=\frac{4190 J}{kg \cdot ^{\circ}C}(10 kg)(100^{\circ}C - 0^{\circ}C ) = 4,190,000 J$$
Work Step by Step
Heating the water through a certain temperature difference takes almost ten times the energy that it does for steel. This is not surprising, because water has a large specific heat capacity.
