Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 15 - Think and Solve: 37


Calculate the required heat. $$Q = cm \Delta T$$ $$=\frac{1 cal}{g \cdot ^{\circ}C}(50000 g)(20^{\circ}C ) = 1000000 cal = 1000 kcal$$ Now convert to joules. $$1000000 cal \frac{4.19 J}{1 cal} = 4190 kJ$$

Work Step by Step

The conversion factor is on page 289.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.