## Conceptual Physics (12th Edition)

Calculate the required heat. $$Q = cm \Delta T$$ $$=\frac{1 cal}{g \cdot ^{\circ}C}(50000 g)(20^{\circ}C ) = 1000000 cal = 1000 kcal$$ Now convert to joules. $$1000000 cal \frac{4.19 J}{1 cal} = 4190 kJ$$