Answer
a). The linear speed of the descending mass will be (3) less than $\sqrt (2gh)$ as there is an external force tension (T) which is non-conservative and acts in the direction opposite to motion of m. Hence, the result.
b). $v=5.84m/s$
Work Step by Step
a). The linear speed of the descending mass will be (3) less than $\sqrt (2gh)$ as there is an external force tension (T) which is non-conservative and acts in the direction opposite to motion of m. Hence, the result.
b). $T.R = I \times$ angular acceleration
or, $T.R=\frac{MR^{2}}{2}\times \frac{a}{R}$
or, $T=\frac{Ma}{2}$
$Mg-T=Ma$
or, $a=8.52m/s^{2}$
Now from $v^{2}=u^{2}+2ah=0+2\times8.52\times2$
$v=5.84m/s$
