Chapter 8 - Rotational Motion and Equilibrium - Learning Path Questions and Exercises - Exercises - Page 307: 48

a). $T=F.d=15\times0.9=13.5 Nm$ $\theta=120^{\circ}=\frac{2pi}{3}$ Work done = $13.5\times\frac{2pi}{3}=28.3J$ b). Power delivered $=\frac{work}{time}=\frac{28.3}{2}=14.15J$

a). $T=F.d=15\times0.9=13.5 Nm$ $\theta=120^{\circ}=\frac{2pi}{3}$ Work done = $13.5\times\frac{2pi}{3}=28.3J$ b). Power delivered $=\frac{work}{time}=\frac{28.3}{2}=14.15J$