Answer
$ a). 2.9325 Nm$
$b). 58.65N$
Work Step by Step
a). Torque = $I \times $ angular acceleration
=$0.55\times4.55=2.5025Nm$
$T_{applied} = T_{f} + 2.5025=0.43+2.5025Nm=2.9325Nm$
b). $F=\frac{T_{applied}}{r}=\frac{2.9325}{0.05}=58.65N$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 8 - Rotational Motion and Equilibrium - Learning Path Questions and Exercises - Exercises - Page 307: 40
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
