Answer
$6.4Nm$
Work Step by Step
Torque $=I \times$ angular acceleration,
$I=\frac{2}{5}mr^{2}=\frac{2}{5}\times20\times0.2^{2}=0.32$
Thus, torque = $0.32\times20=6.4Nm$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 8 - Rotational Motion and Equilibrium - Learning Path Questions and Exercises - Exercises - Page 306: 35
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