Chapter 8 - Rotational Motion and Equilibrium - Learning Path Questions and Exercises - Exercises - Page 306: 34

$1.52\times10^{4} rad/s^{2}$

The torque of a solid disc pulley of mass M and radius R is $=\frac{MR^{2}}{2}\times $ angular acceleration Thus, angular acceleration =$\frac{2\times6.4}{0.15\times0.075^{2}}=1.52\times10^{4} rad/s^{2}$