College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 8 - Rotational Motion and Equilibrium - Learning Path Questions and Exercises - Exercises - Page 306: 30

Answer

$T_{1}=20.79N$ $T_{2}=14.7N$

Work Step by Step

Balancing the forces horizontally, $T_{1}sin45^{\circ}=T_{2}$ $T_{1}=\sqrt 2T_{2}$ .... equation (1) Balancing the forces vertically, $T_{1}cos45^{\circ}=mg$ $T_{1}=20.79N$ Hence, from equation (1), $T_{2}=14.7N$
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