College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 7 - Circular Motion and Gravitation - Learning Path Questions and Exercises - Exercises - Page 261: 31

Answer

$1.34m/s$

Work Step by Step

$a_{c}=\frac{v^{2}}{r}$ $v=\sqrt (a_{c}r)=\sqrt (1.5\times1.2)=1.34m/s$
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