Answer
$1.1rad/s$ down.
Work Step by Step
$\theta=1.75\times2pi=11rad$
Now, $v=u+at=0+at$
$t=\frac{u}{t}=\frac{15}{1.5}=10s$
S0, average angular velocity =$\frac{11rad}{10s}=1.1rad/s$ down.
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 7 - Circular Motion and Gravitation - Learning Path Questions and Exercises - Exercises - Page 261: 29
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