College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 7 - Circular Motion and Gravitation - Learning Path Questions and Exercises - Exercises - Page 261: 29


$1.1rad/s$ down.

Work Step by Step

$\theta=1.75\times2pi=11rad$ Now, $v=u+at=0+at$ $t=\frac{u}{t}=\frac{15}{1.5}=10s$ S0, average angular velocity =$\frac{11rad}{10s}=1.1rad/s$ down.
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