College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 7 - Circular Motion and Gravitation - Learning Path Questions and Exercises - Exercises - Page 261: 27


$\omega=0.634rad/s$ $v=1.11m/s$

Work Step by Step

$\theta=\frac{S}{r}=\frac{2.55}{1.75}=1.457rad$ $\omega=\frac{1.457}{2.3}=0.634rad/s$ $v=r\omega=2\times\frac{\frac{2.55}{2.00}}{2.3}=1.11m/s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.