College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 5 - Work and Energy - Learning Path Questions and Exercises - Exercises - Page 175: 21

Answer

a). (1) $\sqrt 2$ b). $900J$

Work Step by Step

a). $W^{'}=2W=2\times\frac{1}{2}kx^{2}=\frac{1}{2}k(\sqrt 2x)^{2}$ So, if twice the amount of work is done, the stretch increase by factor of $\sqrt 2$. b). $100J=\frac{1}{2}\times k\times 0.01^{2}$ Now, $W^{'}=\frac{1}{2}\times k \times 0.03^{2}$ From above 2 equations, $W^{'}=9\times100=900J$
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