Answer
a). $147.5kJ$
b). $-122.5kJ$
c). $25kJ$
Work Step by Step
a). $h=\frac{1}{2}at^{2}=25m$
$F=m(g+a)=500(9.8+2)=5900N$
$W=5900\times25=147.5kJ$
b). $W=mgh=500\times(-9.8)\times25=-122.5kJ$
c). Net work done on helicopter $W=147.5-122.5=25kJ$