#### Answer

$\frac{W}{4}$

#### Work Step by Step

Work done in first case = change in kinetic energy =$\frac{1}{2}mv^{2}-0=W$
In the second case, work done =$\frac{1}{2}m(\frac{v}{2})^{2}-0=\frac{W}{4}$
Thus, work required =$\frac{W}{4}$

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Published by
Pearson

ISBN 10:
0-32160-183-1

ISBN 13:
978-0-32160-183-4

$\frac{W}{4}$

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