College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 5 - Work and Energy - Learning Path Questions and Exercises - Conceptual Questions - Page 173: 9



Work Step by Step

Work done in first case = change in kinetic energy =$\frac{1}{2}mv^{2}-0=W$ In the second case, work done =$\frac{1}{2}m(\frac{v}{2})^{2}-0=\frac{W}{4}$ Thus, work required =$\frac{W}{4}$
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