## College Physics (7th Edition)

$v_{B}=2v_{A}$ $m_{A}=4m_{B}$ Kinetic energy of Car A =$\frac{1}{2}m_{A}v_{A}^{2}=\frac{1}{2}\times4m_{B}\times\frac{1}{4}v_{B}^{2}=\frac{1}{2}m_{B}v_{B}^{2}$=Kinetic energy of Car B