Answer
$\sqrt 2v$
Work Step by Step
From the problem, work done = change in kinetic energy =$\frac{1}{2}mv^{2}-0=W$
Let the required speed =$v^{'}$
So, $\frac{1}{2}m(v^{'})^{2}-0=2W$
From above 2 equations, we get $v^{'}=\sqrt 2v$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 5 - Work and Energy - Learning Path Questions and Exercises - Conceptual Questions - Page 173: 10
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