College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 139: 75

Answer

a). $30^{\circ}$ b). $0.577$

Work Step by Step

As per result of problem 73, coefficient of static friction = $tan\theta$ a). The angle is independent of the mass or contact area. So, the angle will be same as in the case of the smaller box. So, $\theta=30^{\circ}$ b). Coefficient of friction =$tan30^{\circ}=0.577$
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