Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 139: 70

$0.212$

$a=\frac{v^{2}-u^{2}}{2S}$ F=coefficient of friction$ \times mg=ma$ Coefficient of friction $= \frac{a}{g}$ Therefore, coefficient of kinetic friction$=\frac{v^{2}-u^{2}}{2gS}=\frac{2.5^{2}}{2\times1.5\times9.8}=0.212$