College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 138: 56

Answer

Acceleration of smaller mass is $1.089m/s^{2}$ in upward direction.

Work Step by Step

$m_{1}=0.2kg$ $m_{2}=0.25kg$ As the configuration is same as Atwood machine, so, $a=\frac{m_{2}-m_{1}}{m_{1}+m_{2}}g=\frac{0.25-0.2}{0.45}9.8=1.089m/s^{2}$ Hence, acceleration of smaller mass is $1.089m/s^{2}$ in upward direction.
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