College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 138: 53



Work Step by Step

$v^{2}=u^{2}+2aS$ or, $300^{2}=0+2a\times 0.750$ $a=6\times10^{4}m/s$ So, $F=ma=0.025\times6\times10^{4}N=1500N$
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