College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 97: 9


$2.5 m$ at an angle of $53^{\circ}$ with respect to x-axis.

Work Step by Step

$v_{x}=0.6m/s$ $v_{y}=0.8m/s$ Resultant $v=\sqrt (0.6^{2}+0.8^{2})=1 m/s$ In t=2.5 s, displacement=2.5 m. $\theta=tan^{-1}(\frac{0.8}{0.6})=53^{\circ}$ with respect to x-axis.
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