College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 97: 13



Work Step by Step

a). a=$0.75 m/s^{2}$ After t=4s, in negative y-direction,$S=ut+\frac{1}{2}at^{2}=0+0.5\times0.75\times4^{2}=6m$ After t=4s, in positive x-direction, $S=3\times4=12m$ So, position of the particle is (12m,-6m)
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