College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 97: 10


$\theta=28.3^{\circ}$ with respect to the ground.

Work Step by Step

Wind's horizontal velocity = $10km/hr=10\times\frac{1000m}{3600s}=2.78m/s$ Vertical velocity $=1.5m/s$ So, with respect to the ground, $\theta=tan^{-1} (\frac{1.5}{2.78})=28.3^{\circ}$
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