## College Physics (7th Edition)

$\theta=28.3^{\circ}$ with respect to the ground.
Wind's horizontal velocity = $10km/hr=10\times\frac{1000m}{3600s}=2.78m/s$ Vertical velocity $=1.5m/s$ So, with respect to the ground, $\theta=tan^{-1} (\frac{1.5}{2.78})=28.3^{\circ}$