#### Answer

a). $ 261m/s$
b). $ 17.5^{\circ}$

#### Work Step by Step

a). $v=\sqrt (250^{2}+75^{2})=261m/s$
b). $sin \theta = \frac{75}{250}=0.3$
$\theta=17.5^{\circ}$

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Published by
Pearson

ISBN 10:
0-32160-183-1

ISBN 13:
978-0-32160-183-4

a). $ 261m/s$
b). $ 17.5^{\circ}$

a). $v=\sqrt (250^{2}+75^{2})=261m/s$
b). $sin \theta = \frac{75}{250}=0.3$
$\theta=17.5^{\circ}$

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