Answer
$a).$ (1) travelling with the current
$b).$ 6.67 m/s
Work Step by Step
a). $\frac{400m}{15s}=26.67m/s>20m/s$, so the boat is going with the current.
b). The current is $26.67m/s-20m/s=6.67m/s$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 101: 80
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