## College Physics (7th Edition)

$0.56m/s$ horizontally away from the shopper
Vertical component of shopper velocity $=0.75 \times sin41.8^{\circ}=0.5m/s$ From shopper's perspective difference in speed =$0.5m/s-0.5m/s=0$ Horizontal component of shopper velocity$=0.75\times cos41.8^{\circ}=0.56m/s$ Hence, the answer is $0.56m/s$ horizontally away from the shopper.