College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 102: 83


$0.56m/s$ horizontally away from the shopper

Work Step by Step

Vertical component of shopper velocity $=0.75 \times sin41.8^{\circ}=0.5m/s$ From shopper's perspective difference in speed =$0.5m/s-0.5m/s=0$ Horizontal component of shopper velocity$=0.75\times cos41.8^{\circ}=0.56m/s$ Hence, the answer is $0.56m/s$ horizontally away from the shopper.
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