College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 25 - Vision and Optical Instruments - Learning Path Questions and Exercises - Exercises - Page 871: 8

Answer

a). (1) nearsightedness, b). Diverging lens , $-0.08D$

Work Step by Step

a). She has (1) nearsightedness. Because for a normal eye the far point is infinity. But in this case the far point is less than that hence person with such problem have nearsightedness i.e. she can see nearby objects clearly but not far away objects. b). Type of lens required for correction is diverging lens. $do=infinity$ $di=-12.5m$ $P=\frac{1}{do}+\frac{1}{di}=\frac{1}{infinity}+\frac{1}{-12.5}=-0.08D$
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