#### Answer

Power of top half of the lens is $-0.2D$ and that of the lower half is $+2.57D$

#### Work Step by Step

The doctor recommended bifocal lenses.
For upper half :-
$P_{upper}=\frac{1}{f}=\frac{1}{do}+\frac{1}{di}=\frac{1}{infinity}+\frac{1}{-5}=-0.2D$
For lower half :-
$P_{lower}=\frac{1}{f}=\frac{1}{do}+\frac{1}{di}=\frac{1}{0.25}+\frac{1}{-0.7}=+2.57D$