Answer
a) +5.0 D
b) -2.0 D
Work Step by Step
a)Focal length f= 20cm= $20\times10^{-2}m$
Power $P=\frac{1}{f}=\frac{1}{20\times10^{-2}m}= +5.0 D$
b) $f= -50\times10^{-2}m$
$P= \frac{1}{-50\times10^{-2}m}= -2.0 D$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 25 - Vision and Optical Instruments - Learning Path Questions and Exercises - Exercises - Page 871: 1
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