Answer
$a). 8.45s$
$b).$ Distance traversed by car $=132.1m$
Distance traversed by motorcycle$=157.1m$
$c).13.22m$
Work Step by Step
a). Distance covered by motorcycle is 25m more than that of car till they meet in time t.
Car acceleration rate $=3.7m/s^{2}$
Motorcycle acceleration rate $=4.4m/s^{2}$
So, applying $S=ut+\frac{1}{2}at^{2}$
$4.4t^{2}=3.7t^{2}+2\times25$
$t=8.45s$
b). Distance traversed by car $=\frac{1}{2}\times3.7t^{2}=132.1m$
Distance traversed by motorcycle $=\frac{1}{2}\times4.4t^{2}=157.1m$
c). After 2s, total time$=10.45s$
So, the motorcycle will be ahead of the car by $=\frac{1}{2}\times4.4t^{2}-\frac{1}{2}\times3.7t^{2}-25 =13.22m$
