College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 2 - Kinematics: Description of Motion - Learning Path Questions and Exercises - Exercises - Page 64: 74

Answer

$a). 14m/s$ $b). 8.85m/s$ $c). 2.33s$

Work Step by Step

a). $v^{2}=u^{2}+2aS$ $v^{2}=0+2\times 9.8 \times 10$ $v=14m/s$ b). $0=u^{2}-2\times 9.8\times 4$ $u=8.85m/s$ c). $S=ut+\frac{1}{2}at^{2}$ So, $10=0+0.5\times 9.8\times t^{2}$ $t=1.43s$ Also, $4=0+0.5\times 9.8\times t^{2}$ $t=0.9s$ Total time $=2.33s$
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