College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 2 - Kinematics: Description of Motion - Learning Path Questions and Exercises - Exercises - Page 64: 75


$a). 155 m/s$ $b). 2225.76m$ $c). 28.72s$

Work Step by Step

a). $v^{2}=0+2aS$ $v^{2}=2\times 12\times 1000$ $v=155m/s$ b). $0=155^{2}-2\times 9.8\times h$ $h=1225.76m$ Total maximum height=$1225.76+1000=2225.76m$ c). For first 1000m of flight, $t=\frac{v-u}{a}=\frac{155-0}{12}=12.9s$ Next, $t=\frac{v-u}{g}=\frac{0-155}{-9.8}=15.82s$ Total time taken $=12.9+15.82=28.72s$
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