College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 2 - Kinematics: Description of Motion - Learning Path Questions and Exercises - Exercises - Page 63: 65

Answer

68.89m.

Work Step by Step

On the Moon, the acceleration due to gravity is $\frac{1}{6}th$ that of earth $=\frac{1}{6}\times 9.8 m/s^{2}=1.633 m/s^{2}$ $v^{2}=u^{2}+2aS$ $0=15^{2}-2\times 1.633\times S$ $S=68.89m$
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