College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 2 - Kinematics: Description of Motion - Learning Path Questions and Exercises - Exercises - Page 63: 63

Answer

To spend twice the time in air, the ball should be thrown 4 times the height.

Work Step by Step

$v=u+at$, (u being the velocity during throwing up) $0=u-9.8t\,$ $u=9.8t$ Now, $S=ut+\frac{1}{2}at^{2}=9.8t^{2}-\frac{1}{2}\times 9.8t^{2}$ $S=4.9t^{2}$ So, to spend twice the time in air, the ball should be thrown 4 times the height.
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