## College Physics (7th Edition)

a). For free fall, $v=u+at=0-gt=-9.8t\, m/s$ , we consider downwards to be negative. Graph is as shown. b). For free fall, $S=ut+\frac{1}{2}at^{2}=0-0.5\times 9.8t^{2}=-4.9t^{2}$ So, $y=-4.9t^{2}$. Graph is as shown.
a). For free fall, $v=u+at=0-gt=-9.8t\, m/s$ , we consider downwards to be negative. Graph is as shown. b). For free fall, $S=ut+\frac{1}{2}at^{2}=0-0.5\times 9.8t^{2}=-4.9t^{2}$ So, $y=-4.9t^{2}$. Graph is as shown.