Answer
a) (1) $-x$
b) $1.04\times10^{-6}T$
Work Step by Step
a). Magnetic field is towards left i.e. (-x) direction. (1)
b). $F=qvB$
or, $B=\frac{F}{qv}=\frac{5\times10^{-19}}{1.6\times10^{-9}\times3\times10^{6}}=1.04\times10^{-6}T$
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