Answer
$11.53^{\circ} $ from the vertical
Work Step by Step
$F=qvBsin\theta$
or, $sin\theta=\frac{F}{qvB}=\frac{5}{0.25\times2\times100\times0.5}=0.2$
Thus, $\theta=11.53^{\circ}$ w.r.t the vertical.
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 19 - Magnetism - Learning Path Questions and Exercises - Exercises - Page 691: 6
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