College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 19 - Magnetism - Learning Path Questions and Exercises - Exercises - Page 691: 4

Answer

a) $F=qvBsin\theta$ Based on the given conditions , as per the right hand rule, force will be into the page (1) b) $F=qvB$ or, $B=\frac{F}{qv}=\frac{20}{0.25\times2\times100}=0.4T$

Work Step by Step

a) $F=qvBsin\theta$ Based on the given conditions , as per the right hand rule, force will be into the page (1) b) $F=qvB$ or, $B=\frac{F}{qv}=\frac{20}{0.25\times2\times100}=0.4T$
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