Answer
a) $F=qvBsin\theta$
Based on the given conditions , as per the right hand rule, force will be into the page (1)
b) $F=qvB$
or, $B=\frac{F}{qv}=\frac{20}{0.25\times2\times100}=0.4T$
Work Step by Step
a) $F=qvBsin\theta$
Based on the given conditions , as per the right hand rule, force will be into the page (1)
b) $F=qvB$
or, $B=\frac{F}{qv}=\frac{20}{0.25\times2\times100}=0.4T$