College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Review & Synthesis: Chapters 9-12 - MCAT Review - Page 470: 3


The correct answer is: (d) $1.0\times 10^{-2}~W/m^2$

Work Step by Step

We can find the intensity when the sound level is 100 dB: $10~log~\frac{I}{I_0} = \beta$ $10~log~\frac{I}{I_0} = 100$ $log~\frac{I}{I_0} = 10$ $\frac{I}{I_0} = 10^{10}$ $I = 10^{10}~I_0$ $I = 10^{10}~(1.0\times 10^{-12}~W/m^2)$ $I = 1.0\times 10^{-2}~W/m^2$ The correct answer is: (d) $1.0\times 10^{-2}~W/m^2$
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