## College Physics (4th Edition)

The correct answer is: (d) $1.0\times 10^{-2}~W/m^2$
We can find the intensity when the sound level is 100 dB: $10~log~\frac{I}{I_0} = \beta$ $10~log~\frac{I}{I_0} = 100$ $log~\frac{I}{I_0} = 10$ $\frac{I}{I_0} = 10^{10}$ $I = 10^{10}~I_0$ $I = 10^{10}~(1.0\times 10^{-12}~W/m^2)$ $I = 1.0\times 10^{-2}~W/m^2$ The correct answer is: (d) $1.0\times 10^{-2}~W/m^2$