College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Review & Synthesis: Chapters 9-12 - MCAT Review - Page 470: 1

Answer

The correct answer is: (a) $1\times 10^{-3}~m^3$

Work Step by Step

Since the weight is $10~N$ less in the water, the buoyant force in the water is $10~N$. The buoyant force is equal to the weight of the water displaced by the brick. Note that $10~N$ of water has a mass of $1.0~kg$. We can find the volume of $1.0~kg$ of water: $V = \frac{m_w}{\rho_w}$ $V = \frac{1.0~kg}{1000~kg/m^3}$ $V = 1\times 10^{-3}~m^3$ Since the volume of the brick is equal to the volume of the water that was displaced, the volume of the brick is $~1\times 10^{-3}~m^3$ The correct answer is: (a) $1\times 10^{-3}~m^3$
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