College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Review & Synthesis: Chapters 9-12 - MCAT Review - Page 470: 13


The correct answer is: C. $2\times 10^3~N/m^2$

Work Step by Step

We can find the gauge pressure difference for a depth of 20 cm in the water: $\Delta P_g = \rho~g~\Delta h$ $\Delta P_g = (1000~kg/m^3)(10~m/s^2)(0.20~m)$ $\Delta P_g = 2000~Pa$ The correct answer is: C. $2\times 10^3~N/m^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.