College Physics (4th Edition)

The correct answer is: C. $2\times 10^3~N/m^2$
We can find the gauge pressure difference for a depth of 20 cm in the water: $\Delta P_g = \rho~g~\Delta h$ $\Delta P_g = (1000~kg/m^3)(10~m/s^2)(0.20~m)$ $\Delta P_g = 2000~Pa$ The correct answer is: C. $2\times 10^3~N/m^2$