College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Review & Synthesis: Chapters 6-8 - Review Exercises - Page 323: 8


The acceleration of the block is $~3.7~m/s^2$

Work Step by Step

We can find the acceleration of the block: $\sum F = ma$ $mg~sin~\theta-mg~cos~\theta~\mu_k = ma$ $a = g~(sin~\theta-\mu_k~cos~\theta)$ $a = (9.80~m/s^2)~(sin~53^{\circ}-(0.70)~cos~53^{\circ})$ $a = 3.7~m/s^2$ The acceleration of the block is $~3.7~m/s^2$.
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